Math 7

basic statistics

Week 4

Posted by math7 on January 28, 2006

– Due Monday, 1/30/06, Problems 3,4,5,6 on page 30
* Study room cancelled for Tuesday night.
– Due Wednesday, 2/1/06, Problems 7-12 on page 31
– Due Friday, 2/3/06, Problems 1,2,6,7,10,11 on page 36,37.

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5 Responses to “Week 4”

  1. Anonymous said

    – Due Friday, 1/27,06, Problems 1-5 on pages 30-31.
    Are we suppose to repeat problems 3,4, and 5? I don’t get it…If we
    ‘re suppose to repeat it, good. But if that’s not the case, I hope Prof. Tucker doesn’t get the numbers confused anymore.

  2. ucalirvine said

    Hey good eye. I didn’t catch that. Guess I did the hw already.

  3. ucalirvine said

    Answers I got for #7 pg. 31

    P([T=6])= 64/729
    P([T=5])= 64/243
    P([T>=5])= (64/729)+(64/243)= 256/729

    Can anyone confirm?

  4. ucalirvine said

    For #8 I got:

    P([W>=0])= 1/729
    P([W>=1])= (1/729)+(4/243)= 13/729
    P([W>=2])= (13/729)+(60/729)= 73/729

    Can anyone confirm? Any clues to Prove:9,10,12?

  5. Anonymous said

    #8 is wrong. I believe the right answer is:

    Compute:

    P([W>=2])= 3/10
    P([W>=0])= 2/10+1/10+3/10= 6/10= 3/5
    P([W>=1])= 1/10+3/10= 4/10= 2/5

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